Gujarat Board GSEB Textbook Solutions Class 6 Maths Chapter 10 Mensuration InText Questions and Answers.

## Gujarat Board Textbook Solutions Class 6 Maths Chapter 10 Mensuration InText Questions

Try These (Page 206)

Question 1.

Measure and write the length of the four sides of the top of your study table.

AB = ________ cm

BC = ________ cm

CD = ________ cm

DA = ________ cm

Now, the sum of the lengths of the four sides = AB + BC + CD + DA

= ________ cm + ________ cm + _______ cm + _______ cm = _______ cm

What is the perimeter of the page?

Solution:

AB = 140 cm,

BC = 80 cm,

CD = 140 cm,

DA = 80 cm

∴ AB + BC + CD + DA

= 140 cm + 80 cm + 140 cm + 80 cm = 440 cm

The perimeter = 440 cm

Note: This is an activity so the measures of AB,BC,CD and DA will be different for different table tops.

Question 2.

Measure and write the lengths of the four sides of a page of your notebook. The sum of the lengths of the four sides

= AB + BC + CD + DA

= _________ cm + _________ cm + _________ cm + _________ cm = _________ cm

What is the perimeter of the page?

Solution:

Please try yourself.

Question 3.

Meera went to a park 150 m long and 80 m wide. She took one complete round on its boundary. What is the distance covered by her?

Solution:

Length of the park = 150 m

The breadth of the park = 80 m

The perimeter of the park

= 150 m + 80 m + 150 m + 80 m = 460 m

∴ Distance covered by Meera in going one complete round of the park = 460 m.

Question 4.

Find the perimeter of the following figures:

(a) Perimeter = AB + BC + CD + DA = ________ + ________ + ________ + = ________

(b) Perimeter = AB + BC + CD + DA = ________ + ________ + ________ + = ________

(c) Perimeter = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA

= ________ + ________ + ________ + ________ + ________ + ________ + ________ + ________ + ________ + ________ + ________ + ________ = ________

(d) Perimeter = AB + BC + CD + DE + EF + FA________ + ________ + ________ + ________ + ________ + ________ = ________

Note: For finding the perimeter of any closed figure made up entirely of the line segment, simply find the sum of the lengths of all the sides.

Solution:

(a) ∵ AB = 40 cm, BC = 10 cm,

AD = 10 cm and DC = 40 cm

∴ Perimeter = AB + BC + AD + DC

= 40 cm + 10 cm + 10 cm + 40 cm = 100 cm

(b) ∵ AB = 5 cm, BC = 5 cm,

CD = 5 cm and AD = 5 cm

∴ Perimeter = AB + BC + CD + AD

= 5 cm + 5 cm + 5 cm + 5 cm = 20 cm

(c) Here, perimeter = AB + BC + CD + DE + EF + FG + GH + HI + IJ + JK + KL + LA

= 1 cm + 3 cm + 3 cm + 1 cm + 3 cm

+ 3 cm + 1 cm + 3 cm + 3 cm + 1 cm

+ 3 cm + 3 cm = 28 cm

(d) Here, perimeter=AB + BC + CD + DE + EF + FA

= 100 m + 120 m + 90 m + 45 m + 60 m + 80 m = 495 m

Try These (Page 208)

Question 1.

Find the perimeter of the following rectangles:

Solution:

Do yourself.

Try These (Page 211)

Question 1.

Find various objects from your surroundings that have regular shapes and find their perimeters.

Solution:

It is project work. You can find objects having regular shapes such as a ‘nameplate’ a ‘road signal’, etc. Measure their sides and find perimeters.

Try These (Page 215)

Question 1.

Draw any circle on a graph sheet. Count the squares and use them to estimate the area of the circular region.

Solution:

It is an ‘activity’. Please do it yourself.

Question 2.

Trace shapes of leaves, flower petals, and other such objects on the graph paper and find their areas.

Solution:

It is an ‘activity’. Please do it yourself.

Try These (Page 217)

Question 1.

Find the area on the floor of your classroom.

Solution:

This is an activity. Please do it yourself.

Question 2.

Find the area of anyone’s door in your house.

Solution:

This is an activity. Please do it yourself.